XPost: sci.physics.relativity   
   From: physfitfreak@gmail.com   
      
   On 2/23/25 12:15 PM, Physfitfreak wrote:   
   > On 2/16/25 9:47 PM, Physfitfreak wrote:   
   >> On 2/16/25 9:42 PM, Physfitfreak wrote:   
   >>> My guess is that the information of its disappearance will travel   
   >>> towards Earth at, or below, the light's speed (i.e. max speed for any   
   >>> physical quantity) and when it reaches Earth, the path of Earth   
   >>> motion becomes almost linear from that moment on.   
   >>   
   >>   
   >> Actually it can crush the Earth into pieces because parts of the Earth   
   >> closer to the absent Sun's position will begin moving linearly while   
   >> the rest of the Earth still continues on the usual orbit. So a   
   >> crushing of Earth into itself will take place for a couple of seconds   
   >> or so.   
   >>   
   >>   
   >   
   >   
   > Huh.. no not a couple of seconds. Just over 40 milliseconds. In the back   
   > of my mind I had the sound in the telephone calls to Iran in the old   
   > days in my mind. You'd sometimes hear your echo coming back in about a   
   > couple of seconds.   
   >   
   > But 40 milliseconds of a huge spherical surface of the change in gravity   
   > passing through the Earth could itself be quite significant. One can sit   
   > and do a back of the envelope calculation of some of the consequences,   
   > looking at, say, only the time at which half of Earth is on orbit around   
   > the sun and the other half is moving linearly. I'll leave it to those   
   > interested to do that.   
   >   
   > Then after a very rough estimate, do a better analysis as a physicist   
   > can, still within the "back of the envelope" scope of the work of   
   > course, but showing the time dependent propagation of the result over   
   > the entire mass of the earth throughout that 40 milliseconds. This last   
   > one, although still a baby problem, is not for the "engineers".   
   > "Engineers" like the dead "Jim Pennino" could only finger themselves   
   > about it.   
   >   
   >   
   >   
      
      
   Ok, .. another 10 minutes of rest here will give my dick a chance to do   
   the back of the envelope calculation.   
      
   My dick says, in 40 milliseconds Earth moves on the orbit 30 meters. Its   
   distance to the position of Earth had it moved linearly is about 6   
   nanometers, which is about 20 silicon atoms inside stone, the way   
   silicon is distributed in it (surrounded by oxygens). I'm looking only   
   at the crust.   
      
   So _EVERY_ silicon atom of the crust in Earth will penetrate through 20   
   other silicon atoms, not at once, but in turns, as a wave traveling for   
   40 milliseconds across the whole crust.   
      
   This is the case for Sun suddenly disappearing. Do the back of the   
   envelope calculations for the case of Sun losing, say 20 Earth masses in   
   one huge burst in a large storm. Assume the 20 Earth mass disappears   
   instantly, and find out what kind of crashes appears in the crust on   
   Earth as a result.   
      
   --- SoupGate-DOS v1.05   
    * Origin: you cannot sedate... all the things you hate (1:229/2)