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|    sci.physics    |    Physical laws, properties, etc.    |    178,923 messages    |
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|    Message 178,425 of 178,923    |
|    Thomas 'PointedEars' Lahn to Thomas 'PointedEars' Lahn    |
|    Re: Why would the center of the earth ha    |
|    07 Dec 25 17:35:33    |
      From: PointedEars@web.de              Thomas 'PointedEars' Lahn wrote:       > First of all, it is not good to think of gravitation as a property of an       > object as in "Earth *has* gravity". That is NOT how it works. [This is       > frequently taught wrong in schools.] Instead, it is an *interaction*       > _between_ objects. According to Newton's theory, objects _attract each       > other_ because they have non-zero mass. So (according to Newton) it is not       > so that "earth does gravity" but that Terra (_Earth_) has non-zero mass,              ["non-zero X" simply means "X is not equal to zero"]              > and so do other objects (including people like you and me), and so everything       > is attracted to everything else. (As the story goes, he realized that an       apple       > and Earth attract each other in the same as Earth and the Moon attract each        ^^^^^^^^^^^       in the same _way_              > other, and Earth and the Sun are attracted to each other: Gravitation was       > *universal*, not limited to Earth. Thus he could also explain how Kepler's       > planetary orbits arose, and predict them.)       >       > One way to understand how the magnitude of the gravitational acceleration at       > the center of Terra is approximately zero is to consider that a test object       > with a negligible non-zero mass (a "test mass") located there will be       > attracted gravitationally by all the matter that surrounds it (which also       > has non-zero mass) in all directions of space approximately in the same way       > (*exactly* in the same way if the planet were spherically-symmetric and had       > a uniform mass density; we know that this is not so for any planet, but it       > is still a good approximation), so the net gravitational force on it and its       > net gravitational acceleration is approximately (would be *exactly*) zero.              Granted, the "incredibly unbroken" one-paragraph sentence above is far too       long, and reminds me of a certain Dr. Fassbinder }:-)              An attempt to rewrite it:              One way to understand how the magnitude of the gravitational acceleration       at the center of Terra is approximately zero is to consider a test object       with a negligible non-zero mass (a "test mass") there. It will be attracted       gravitationally by all the matter that surrounds it (which also has non-zero       mass) in all directions of space approximately in the same way. So the net       gravitational force on it and its net gravitational acceleration are       approximately zero.              [The test object would be attracted *exactly* in the same way if the planet       were spherically-symmetric and had a uniform mass density; we know that this       is not so for any planet, but it is still a good approximation.]              --       PointedEars              Twitter: @PointedEars2       Please do not cc me. / Bitte keine Kopien per E-Mail.              --- SoupGate-Win32 v1.05        * Origin: you cannot sedate... all the things you hate (1:229/2)    |
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