From: PointedEars@web.de   
      
   Thomas 'PointedEars' Lahn wrote:   
   > In vacuum:   
   >   
   >   ∇ × B  = μ₀ (J + ε₀ μ₀ ∂E/∂t) = μ₀ J + (1/c²)   
   ∂E/∂t,    (1)   
      
   The careful reader has probably noticed it: There is an extra μ₀ between the   
   parentheses :'-)   
      
   >   ∇ × E' = -∂B'/∂t,                                       (2)   
   >   
   > where (IIUC) E' is now the contribution to the electric field that is   
   > induced by the change in the magnetic field B' due to the induced current,   
   > that produces Lenz's opposing current ':-)   
      
   --   
   PointedEars   
      
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